What is the derivative of y=tan^2(8x) ?

The derivative of y=tan^2(8x) is 16sec^2(8x)tan(8x)

What is the first derivative of y=tan^2(8x) ?

The first derivative of y=tan^2(8x) is 16sec^2(8x)tan(8x)

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derivative of

y = tan^{2} (8 x)

16 sec^{2} (8 x) tan (8 x)

Solution steps

\frac{d}{d x} (tan^{2} (8 x))

Apply the chain rule:

2 tan (8 x) \frac{d}{d x} (tan (8 x))

= 2 tan (8 x) \frac{d}{d x} (tan (8 x))

\frac{d}{d x} (tan (8 x)) = sec^{2} (8 x) \cdot 8

= 2 tan (8 x) sec^{2} (8 x) \cdot 8

Simplify

= 16 sec^{2} (8 x) tan (8 x)

\int 42 x (x + 1)^{5} d x

\int \frac{1}{2 x ^{2} + 5} d x

\int tan (4 x) sec^{2} (4 x) d x

\int \frac{8}{x ^{2}} cos (\frac{8}{x}) d x

\frac{\partial}{\partial x} (y cos (x + y))

What is the derivative of y=tan^2(8x) ?
The derivative of y=tan^2(8x) is 16sec^2(8x)tan(8x)
What is the first derivative of y=tan^2(8x) ?
The first derivative of y=tan^2(8x) is 16sec^2(8x)tan(8x)