What is the integral of 7\sqrt[3]{x} ?

The integral of 7\sqrt[3]{x} is 21/4 x^{4/3}+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral of 7\sqrt[3]{x}

\frac{21}{4} x^{\frac{4}{3}} + C

Solution steps

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

Apply the Power Rule

: \frac{3}{4} x^{\frac{4}{3}}

= 7 \cdot \frac{3}{4} x^{\frac{4}{3}}

Simplify

7 \cdot \frac{3}{4} x^{\frac{4}{3}} : \frac{21}{4} x^{\frac{4}{3}}

= \frac{21}{4} x^{\frac{4}{3}}

Add a constant to the solution

= \frac{21}{4} x^{\frac{4}{3}} + C

(x^{4} + 3 x)^{- 1}

\int_{0}^{\frac{π}{2}} 1 d θ

\frac{d}{d x} (x^{2} + \frac{3456}{x})

\frac{1}{s ( s ^{2} + 81 )}

\frac{d}{d y} (\frac{w ( x + y )}{x y})

What is the integral of 7\sqrt[3]{x} ?
The integral of 7\sqrt[3]{x} is 21/4 x^{4/3}+C