What is the tangent of 10+(20)/(x+1),\at x=3 ?

The tangent of 10+(20)/(x+1),\at x=3 is y=-5/4 x+75/4

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tangent of 10+(20)/(x+1),\at x=3

tangent of

10 + \frac{20}{x + 1}, at x = 3

y = - \frac{5}{4} x + \frac{75}{4}

Solution steps

Find the tangent point:

(3, 15)

Find the slope of

y = 10 + \frac{20}{x + 1} : \frac{d y}{d x} = - \frac{20}{( x + 1 ) ^{2}}

Compute the slope of

y = 10 + \frac{20}{x + 1}

x = 3 : m = - \frac{5}{4}

Find the line with slope m=

- \frac{5}{4}

and passing through

(3, 15) : y = - \frac{5}{4} x + \frac{75}{4}

y = - \frac{5}{4} x + \frac{75}{4}

x \to \frac{π}{2} lim (cos (π + x))

n = 1 \sum \infty \frac{2}{5}

y^{^{'}} - y^{2} = 0, y (0) = 1

\int_{0}^{1} \frac{x ^{8}}{x ^{9} - 1} d x

\int x (x^{2}) d x

What is the tangent of 10+(20)/(x+1),\at x=3 ?
The tangent of 10+(20)/(x+1),\at x=3 is y=-5/4 x+75/4