What is the tangent of f(x)= 4/x ,(-4,-1) ?

The tangent of f(x)= 4/x ,(-4,-1) is y=-1/4 x-2

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tangent of f(x)= 4/x ,(-4,-1)

tangent of

f (x) = \frac{4}{x}, (- 4, - 1)

y = - \frac{1}{4} x - 2

Solution steps

Find the slope of

f (x) = \frac{4}{x} : \frac{df ( x )}{d x} = - \frac{4}{x ^{2}}

Compute the slope of

f (x) = \frac{4}{x}

(- 4, - 1) : m = - \frac{1}{4}

Find the line with slope m=

- \frac{1}{4}

and passing through

(- 4, - 1) : y = - \frac{1}{4} x - 2

y = - \frac{1}{4} x - 2

x \to - 6 lim (\frac{- 9 x}{x + 6})

\int 9 sec^{3} (x) d x

\frac{d ^{2}}{d x ^{2}} (1 - x^{2})

\int 23 e^{x} d x

\int \frac{sin ( 2 x )}{13 + cos ^{2} ( x )} d x

What is the tangent of f(x)= 4/x ,(-4,-1) ?
The tangent of f(x)= 4/x ,(-4,-1) is y=-1/4 x-2