What is area y=4x,x=4,y= 4/x ,x=0 ?

The answer to area y=4x,x=4,y= 4/x ,x=0 is diverges

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area y=4x,x=4,y= 4/x ,x=0

area

y = 4 x, x = 4, y = \frac{4}{x}, x = 0

diverges

Solution steps

Apply the area formula:

\int_{0}^{4} 4 x - \frac{4}{x} d x

Solve

\int_{0}^{4} 4 x - \frac{4}{x} d x :

diverges

The area is:

= diverges

\frac{\partial}{\partial x} (ln (3 y e^{x y}))

\frac{\partial}{\partial x} (8 y e^{x} - ln (z))

\frac{( s + 1 ) ^{3}}{s ^{6}}

\int \frac{1}{( 3 + y ) ^{5}} d y

y^{^{'}} = - \frac{2}{x} y

What is area y=4x,x=4,y= 4/x ,x=0 ?
The answer to area y=4x,x=4,y= 4/x ,x=0 is diverges