What is the tangent of y=e^{6x}cos(pix),(0,1) ?

The tangent of y=e^{6x}cos(pix),(0,1) is y=6x+1

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tangent of y=e^{6x}cos(pix),(0,1)

tangent of

y = e^{6 x} cos (π x), (0, 1)

y = 6 x + 1

Solution steps

Find the slope of

y = e^{6 x} cos (π x) : \frac{d y}{d x} = 6 e^{6 x} cos (π x) - π e^{6 x} sin (π x)

Compute the slope of

y = e^{6 x} cos (π x)

(0, 1) : m = 6

Find the line with slope m=

6

and passing through

(0, 1) : y = 6 x + 1

y = 6 x + 1

y^{^{''}} + 14 y^{^{'}} + 28 y = 6675 e^{2 t} cos (15 t)

\frac{d}{d x} (5 x - 3)

t^{2} sin (t)

\frac{\partial}{\partial x} (x^{2} + y^{2} + 4 z^{2})

\frac{1 + 5 t}{ln ( t ^{2} )}

What is the tangent of y=e^{6x}cos(pix),(0,1) ?
The tangent of y=e^{6x}cos(pix),(0,1) is y=6x+1