What is the integral from 1 to 10 of 5x^{-2} ?

The integral from 1 to 10 of 5x^{-2} is 9/2

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integral from 1 to 10 of 5x^{-2}

\int_{1}^{10} 5 x^{- 2} d x

\frac{9}{2}

Decimal Notation

4.5

Solution steps

\int_{1}^{10} 5 x^{- 2} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 5 \cdot \int_{1}^{10} x^{- 2} d x

Apply the Power Rule

: [- \frac{1}{x}]_{1}^{10}

= 5 [- \frac{1}{x}]_{1}^{10}

Compute the boundaries:

\frac{9}{10}

= 5 \cdot \frac{9}{10}

Simplify

= \frac{9}{2}

\frac{d}{d x} (2 x^{3} - 5 x^{2} + 3 x - 1)

\frac{1}{s ( s ^{2} + 100 s + 10000 )}

\frac{\partial}{\partial z} (2 x y)

f (x) = \frac{1}{x ^{7}}

\int (cos (2 x)) d x

What is the integral from 1 to 10 of 5x^{-2} ?
The integral from 1 to 10 of 5x^{-2} is 9/2