derivative of arccot(x/8)

Lösung

\frac{d}{d x} (arccot (\frac{x}{8}))

- \frac{8}{x ^{2} + 64}

Schritte zur Lösung

\frac{d}{d x} (arccot (\frac{x}{8}))

Wende die Kettenregel an:

- \frac{1}{( \frac{x}{8} ) ^{2} + 1} \frac{d}{d x} (\frac{x}{8})

= - \frac{1}{( \frac{x}{8} ) ^{2} + 1} \frac{d}{d x} (\frac{x}{8})

\frac{d}{d x} (\frac{x}{8}) = \frac{1}{8}

= - \frac{1}{( \frac{x}{8} ) ^{2} + 1} \cdot \frac{1}{8}

Vereinfache

- \frac{1}{( \frac{x}{8} ) ^{2} + 1} \cdot \frac{1}{8} : - \frac{8}{x ^{2} + 64}

= - \frac{8}{x ^{2} + 64}

x \to 0 lim ((1 + x)^{\frac{3}{x}})

y^{^{''}} - \frac{5}{t} y^{^{'}} + \frac{18}{t ^{2}} y = 0

\int (2 cot^{2} (x) - 3 tan^{2} (x)) d x

\frac{d}{d y} (x e^{y})

\int x^{2} e^{y} d y