What is the derivative of x^2+4xsin(x) ?

The derivative of x^2+4xsin(x) is 2x+4(sin(x)+xcos(x))

What is the first derivative of x^2+4xsin(x) ?

The first derivative of x^2+4xsin(x) is 2x+4(sin(x)+xcos(x))

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\frac{d}{d x} (x^{2} + 4 x sin (x))

2 x + 4 (sin (x) + x cos (x))

Solution steps

\frac{d}{d x} (x^{2} + 4 x sin (x))

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{2}) + \frac{d}{d x} (4 x sin (x))

\frac{d}{d x} (x^{2}) = 2 x

\frac{d}{d x} (4 x sin (x)) = 4 (sin (x) + x cos (x))

= 2 x + 4 (sin (x) + x cos (x))

\int \frac{- x}{1 - x ^{2}} d x

\int t t - 1 d t

\int \frac{1}{x 4 x ^{2} + 1} d x

(cosh (x))^{^{'}}

\frac{d}{d x} (25)

What is the derivative of x^2+4xsin(x) ?
The derivative of x^2+4xsin(x) is 2x+4(sin(x)+xcos(x))
What is the first derivative of x^2+4xsin(x) ?
The first derivative of x^2+4xsin(x) is 2x+4(sin(x)+xcos(x))