What is the integral from-3 to x^3 of t^3 ?

The integral from-3 to x^3 of t^3 is (x^{12}-81)/4

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integral from-3 to x^3 of t^3

\int_{- 3}^{x^{3}} t^{3} d t

\frac{x ^{12} - 81}{4}

Solution steps

\int_{- 3}^{x^{3}} t^{3} d t

Apply the Power Rule

: [\frac{t ^{4}}{4}]_{- 3}^{x^{3}}

= [\frac{t ^{4}}{4}]_{- 3}^{x^{3}}

Compute the boundaries:

\frac{x ^{12}}{4} - \frac{81}{4}

= \frac{x ^{12}}{4} - \frac{81}{4}

Simplify

= \frac{x ^{12} - 81}{4}

x \to - 2 lim (x^{2} + 9 x + 6)

\int \frac{( 5 - e ^{x} )}{e ^{2 x}} d x

f (x) = x arccos (x)

\frac{\partial}{\partial x} (A (B - x^{2} - y^{2} - z^{2}))

f (x) = (5 x^{6} + 4 x^{3})^{4}

What is the integral from-3 to x^3 of t^3 ?
The integral from-3 to x^3 of t^3 is (x^{12}-81)/4