What is the derivative of y=-2x^2+4x-4 ?

The derivative of y=-2x^2+4x-4 is -4x+4

What is the first derivative of y=-2x^2+4x-4 ?

The first derivative of y=-2x^2+4x-4 is -4x+4

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derivative of

y = - 2 x^{2} + 4 x - 4

- 4 x + 4

Solution steps

\frac{d}{d x} (- 2 x^{2} + 4 x - 4)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= - \frac{d}{d x} (2 x^{2}) + \frac{d}{d x} (4 x) - \frac{d}{d x} (4)

\frac{d}{d x} (2 x^{2}) = 4 x

\frac{d}{d x} (4 x) = 4

\frac{d}{d x} (4) = 0

= - 4 x + 4 - 0

Simplify

= - 4 x + 4

x \to - \infty lim (ln (x))

f (x) = \frac{x ^{2}}{5 + 8 x}

y^{^{''}} + 2 y^{^{'}} = 1 + t^{2} + e^{- 2 t}

\frac{d ^{2} y}{d x ^{2}} + 4 y = sin (2 x)

\frac{d}{d x} (\frac{- x}{y})

What is the derivative of y=-2x^2+4x-4 ?
The derivative of y=-2x^2+4x-4 is -4x+4
What is the first derivative of y=-2x^2+4x-4 ?
The first derivative of y=-2x^2+4x-4 is -4x+4