What is the solution for (dy)/(dx)=y(8x^2+6) ?

The solution for (dy)/(dx)=y(8x^2+6) is y=e^{(8x^3)/3+6x+c_{1}}

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(dy)/(dx)=y(8x^2+6)

\frac{d y}{d x} = y (8 x^{2} + 6)

y = e^{\frac{8 x ^{3}}{3} + 6 x + c_{1}}

Solution steps

\frac{d y}{d x} = y (8 x^{2} + 6)

Solve separable ODE:

y = e^{\frac{8 x ^{3}}{3} + 6 x + c_{1}}

y = e^{\frac{8 x ^{3}}{3} + 6 x + c_{1}}

\int_{e}^{\infty} \frac{ln ( x )}{x} d x

f (x) = \frac{8 x}{x ^{2} + 1}

(4 - t^{2}) y^{^{'}} + 2 t y = 3 t^{2}

\int \frac{1}{2} t^{2} d t

\frac{\partial}{\partial x} (x e^{y} + y e^{- x})

What is the solution for (dy)/(dx)=y(8x^2+6) ?
The solution for (dy)/(dx)=y(8x^2+6) is y=e^{(8x^3)/3+6x+c_{1}}