What is (\partial)/(\partial x)(7e^xcos(yz)) ?

The answer to (\partial)/(\partial x)(7e^xcos(yz)) is 7cos(yz)e^x

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(\partial)/(\partial x)(7e^xcos(yz))

\frac{\partial}{\partial x} (7 e^{x} cos (yz))

7 cos (yz) e^{x}

Solution steps

\frac{\partial}{\partial x} (7 e^{x} cos (yz))

Treat

y, z

as constants

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 7 cos (yz) \frac{\partial}{\partial x} (e^{x})

Apply the common derivative:

\frac{\partial}{\partial x} (e^{x}) = e^{x}

= 7 cos (yz) e^{x}

x^{4} f (x)

(\frac{d y}{d x}) - 3 y = e^{2 x}

y^{^{''}} + 4 y^{^{'}} = 6 e^{- 3 t}

\frac{d y}{d x} + \frac{9 y}{1000 + x} = 0.405

f (x) = 3 sin (x), at x = \frac{π}{4}

What is (\partial)/(\partial x)(7e^xcos(yz)) ?
The answer to (\partial)/(\partial x)(7e^xcos(yz)) is 7cos(yz)e^x