What is the solution for (3x^2+y+3x^3y)dx+(x)dy=0 ?

The solution for (3x^2+y+3x^3y)dx+(x)dy=0 is y=-1/x+(c_{1})/(e^{x^3)x}

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(3x^2+y+3x^3y)dx+(x)dy=0

(3 x^{2} + y + 3 x^{3} y) d x + (x) d y = 0

y = - \frac{1}{x} + \frac{c _{1}}{e ^{x^{3}} x}

Solution steps

(3 x^{2} + y + 3 x^{3} y) d x + (x) d y = 0

Solve linear ODE:

y = - \frac{1}{x} + \frac{c _{1}}{e ^{x^{3}} x}

y = - \frac{1}{x} + \frac{c _{1}}{e ^{x^{3}} x}

\int \frac{1}{1 - ( x + 1 ) ^{2}} d x

\frac{\partial}{\partial y} (ln (x^{2} + y^{2} + z^{2}))

\int \frac{( y - 1 ) ( y - 5 )}{y ^{3} - y ^{2} + 3 y + 5} d y

\int 2 + 6 x d x

n = 1 \sum \infty x^{n + 1}

What is the solution for (3x^2+y+3x^3y)dx+(x)dy=0 ?
The solution for (3x^2+y+3x^3y)dx+(x)dy=0 is y=-1/x+(c_{1})/(e^{x^3)x}