What is the derivative of 5x^3+4x ?

The derivative of 5x^3+4x is 15x^2+4

What is the first derivative of 5x^3+4x ?

The first derivative of 5x^3+4x is 15x^2+4

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derivative of

5 x^{3} + 4 x

15 x^{2} + 4

Solution steps

\frac{d}{d x} (5 x^{3} + 4 x)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (5 x^{3}) + \frac{d}{d x} (4 x)

\frac{d}{d x} (5 x^{3}) = 15 x^{2}

\frac{d}{d x} (4 x) = 4

= 15 x^{2} + 4

\int_{0}^{\infty} \frac{1}{x ^{2} + x} d x

\frac{\partial}{\partial y} (\frac{1}{x ^{2} + y ^{2} + 1})

\frac{d y}{d x} = - 0.05 y

\frac{\partial}{\partial y} (2 x y^{4} - 4)

\int x^{3} (x^{2} + 1)^{8} d x

What is the derivative of 5x^3+4x ?
The derivative of 5x^3+4x is 15x^2+4
What is the first derivative of 5x^3+4x ?
The first derivative of 5x^3+4x is 15x^2+4