What is the d/(d{z)}({x}e^{({y})/({z)}}) ?

The d/(d{z)}({x}e^{({y})/({z)}}) is -(e^{({y})/({z)})/y {x}}{{z}^2}

What is the first d/(d{z)}({x}e^{({y})/({z)}}) ?

The first d/(d{z)}({x}e^{({y})/({z)}}) is -(e^{({y})/({z)})/y {x}}{{z}^2}

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Popular >

\frac{d}{d z} (x e^{\frac{y}{z}})

- \frac{e ^{\frac{y}{z}} y x}{z ^{2}}

Solution steps

\frac{d}{d z} (x e^{\frac{y}{z}})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= x \frac{d}{d z} (e^{\frac{y}{z}})

Apply the chain rule:

e^{\frac{y}{z}} \frac{d}{d z} (\frac{y}{z})

= e^{\frac{y}{z}} \frac{d}{d z} (\frac{y}{z})

\frac{d}{d z} (\frac{y}{z}) = - \frac{y}{z ^{2}}

= x e^{\frac{y}{z}} (- \frac{y}{z ^{2}})

Simplify

x e^{\frac{y}{z}} (- \frac{y}{z ^{2}}) : - \frac{e ^{\frac{y}{z}} y x}{z ^{2}}

= - \frac{e ^{\frac{y}{z}} y x}{z ^{2}}

\int \frac{1}{( a x + b ) ^{4}} d x

\int_{0}^{1} π (y^{2} - y^{4}) d y

\frac{\partial}{\partial x} (z^{2} + 5 x^{2} + y^{2})

\int 3 x^{2} - 4 x d x

\int_{4}^{5} x d x

What is the d/(d{z)}({x}e^{({y})/({z)}}) ?
The d/(d{z)}({x}e^{({y})/({z)}}) is -(e^{({y})/({z)})/y {x}}{{z}^2}
What is the first d/(d{z)}({x}e^{({y})/({z)}}) ?
The first d/(d{z)}({x}e^{({y})/({z)}}) is -(e^{({y})/({z)})/y {x}}{{z}^2}