What is the d/(dt)(5cos(t)) ?

The d/(dt)(5cos(t)) is -5sin(t)

What is the first d/(dt)(5cos(t)) ?

The first d/(dt)(5cos(t)) is -5sin(t)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

\frac{d}{d t} (5 cos (t))

- 5 sin (t)

Solution steps

\frac{d}{d t} (5 cos (t))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 5 \frac{d}{d t} (cos (t))

Apply the common derivative:

\frac{d}{d t} (cos (t)) = - sin (t)

= 5 (- sin (t))

Simplify

= - 5 sin (t)

\int_{0}^{1} \frac{1}{x ^{2} + 16} d x

y^{^{''}} - 5 y^{^{'}} - 2 y = 0

\int_{- 8}^{8} (8 - ∣ x ∣) d x

h \to 0 lim ((x + h)^{2} - x^{2})

\int \frac{x + 1}{x ( x ^{2} + 1 )} d x