What is the derivative of f(x)=e^{2x+1} ?

The derivative of f(x)=e^{2x+1} is e^{2x+1}*2

What is the first derivative of f(x)=e^{2x+1} ?

The first derivative of f(x)=e^{2x+1} is e^{2x+1}*2

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derivative of

f (x) = e^{2 x + 1}

e^{2 x + 1} \cdot 2

Solution steps

\frac{d}{d x} (e^{2 x + 1})

Apply the chain rule:

e^{2 x + 1} \frac{d}{d x} (2 x + 1)

= e^{2 x + 1} \frac{d}{d x} (2 x + 1)

\frac{d}{d x} (2 x + 1) = 2

= e^{2 x + 1} \cdot 2

\frac{d}{d x} (x^{3} + a x^{2} y + b x y^{2} + y^{3})

\int 3 x + 2 cos (5 x) d x

\int e^{0.5 t} d t

x \to 2 lim (\frac{( 3 x - 6 )}{1 - 4 x - 7})

\frac{\partial}{\partial x} (y^{3} + x^{2} y - 3 y)

What is the derivative of f(x)=e^{2x+1} ?
The derivative of f(x)=e^{2x+1} is e^{2x+1}*2
What is the first derivative of f(x)=e^{2x+1} ?
The first derivative of f(x)=e^{2x+1} is e^{2x+1}*2