What is the derivative of \sqrt[3]{8x^4}+1/(x^2) ?

The derivative of \sqrt[3]{8x^4}+1/(x^2) is (8x^3)/(3(x^4)^{2/3)}-2/(x^3)

What is the first derivative of \sqrt[3]{8x^4}+1/(x^2) ?

The first derivative of \sqrt[3]{8x^4}+1/(x^2) is (8x^3)/(3(x^4)^{2/3)}-2/(x^3)

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derivative of

\frac{8 x ^{3}}{3 ( x ^{4} ) ^{\frac{2}{3}}} - \frac{2}{x ^{3}}

Solution steps

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

\frac{d}{d x} (\frac{1}{x ^{2}}) = - \frac{2}{x ^{3}}

= \frac{8 x ^{3}}{3 ( x ^{4} ) ^{\frac{2}{3}}} - \frac{2}{x ^{3}}

\int_{0}^{L} x d x

y^{^{'}} + 4 y = x^{2}

\int_{- 21}^{0} \frac{1}{4 - x} d x

\int 8 cos (x) d x

\int_{0}^{2} 10 x^{3} x^{2} + 4 d x

What is the derivative of \sqrt[3]{8x^4}+1/(x^2) ?
The derivative of \sqrt[3]{8x^4}+1/(x^2) is (8x^3)/(3(x^4)^{2/3)}-2/(x^3)
What is the first derivative of \sqrt[3]{8x^4}+1/(x^2) ?
The first derivative of \sqrt[3]{8x^4}+1/(x^2) is (8x^3)/(3(x^4)^{2/3)}-2/(x^3)