What is (\partial)/(\partial x)(-2xy^2) ?

The answer to (\partial)/(\partial x)(-2xy^2) is -2y^2

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(\partial)/(\partial x)(-2xy^2)

\frac{\partial}{\partial x} (- 2 x y^{2})

- 2 y^{2}

Solution steps

\frac{\partial}{\partial x} (- 2 x y^{2})

Treat

y

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= - 2 y^{2} \frac{\partial}{\partial x} (x)

Apply the common derivative:

\frac{\partial}{\partial x} (x) = 1

= - 2 y^{2} \cdot 1

Simplify

= - 2 y^{2}

\frac{d x}{d t} = x (1 - x)

\int 6 ln (x^{2} - 1) d x

\frac{d}{d t} (ln (t))

\frac{\partial}{\partial x} (e^{- j w n})

\frac{d y}{d x} = \frac{( x - y )}{( x + 2 y )}, y (0) = 1

What is (\partial)/(\partial x)(-2xy^2) ?
The answer to (\partial)/(\partial x)(-2xy^2) is -2y^2