What is the integral from 0 to pi of 9xsin(x) ?

The integral from 0 to pi of 9xsin(x) is 9pi

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integral from 0 to pi of 9xsin(x)

\int_{0}^{π} 9 x sin (x) d x

9 π

Decimal Notation

28.27433 \dots

Solution steps

\int_{0}^{π} 9 x sin (x) d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 9 \cdot \int_{0}^{π} x sin (x) d x

Apply Integration By Parts

: [- x cos (x) - \int - cos (x) d x]_{0}^{π}

= 9 [- x cos (x) - \int - cos (x) d x]_{0}^{π}

\int - cos (x) d x = - sin (x)

= 9 [- x cos (x) - (- sin (x))]_{0}^{π}

Simplify

= 9 [- x cos (x) + sin (x)]_{0}^{π}

Compute the boundaries:

π

= 9 π

\frac{\partial}{\partial x} (y \cdot e^{2 x})

\int_{1}^{4} (3 - ∣ x - 3 ∣) d x

f (x) = \frac{2 x}{x ^{2} - 7}

\frac{d}{d x} (x^{2} + (y - 1)^{2})

x \to \infty lim (25 - x^{3})

What is the integral from 0 to pi of 9xsin(x) ?
The integral from 0 to pi of 9xsin(x) is 9pi