What is the solution for (dy)/(dx)=(y^2)/(x^2)+y/x+1 ?

The solution for (dy)/(dx)=(y^2)/(x^2)+y/x+1 is y=tan(ln(x)+c_{1})x

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(dy)/(dx)=(y^2)/(x^2)+y/x+1

\frac{d y}{d x} = \frac{y ^{2}}{x ^{2}} + \frac{y}{x} + 1

y = tan (ln (x) + c_{1}) x

Solution steps

\frac{d y}{d x} = \frac{y ^{2}}{x ^{2}} + \frac{y}{x} + 1

Solve using substitution:

y = tan (ln (x) + c_{1}) x

y = tan (ln (x) + c_{1}) x

\frac{d}{d x} (\frac{x ^{2} - 10 x + 2}{x ( x ^{2} - 1 )})

\frac{d}{d x} (\frac{x ^{5}}{3 - x ^{4}})

\frac{d}{d x} (\frac{sin ^{2} ( x )}{4})

\frac{d}{d x} (e^{x} ln (x^{2}))

\frac{d y}{d x} = \frac{x y}{x ^{2} + 1}

What is the solution for (dy)/(dx)=(y^2)/(x^2)+y/x+1 ?
The solution for (dy)/(dx)=(y^2)/(x^2)+y/x+1 is y=tan(ln(x)+c_{1})x