What is the integral of (x^2)/2-2x ?

The integral of (x^2)/2-2x is (x^3)/6-x^2+C

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integral of (x^2)/2-2x

\int \frac{x ^{2}}{2} - 2 x d x

\frac{x ^{3}}{6} - x^{2} + C

Solution steps

\int \frac{x ^{2}}{2} - 2 x d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int \frac{x ^{2}}{2} d x - \int 2 x d x

\int \frac{x ^{2}}{2} d x = \frac{x ^{3}}{6}

\int 2 x d x = x^{2}

= \frac{x ^{3}}{6} - x^{2}

Add a constant to the solution

= \frac{x ^{3}}{6} - x^{2} + C

\int \frac{1}{( x + 1 ) ( 3 x + 1 )} d x

\int \frac{x}{5 + x - x ^{2}} d x

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\frac{\partial}{\partial x} (cos^{6} (x^{9} y^{5}))

\int \frac{( 2 x + 3 )}{x} d x

What is the integral of (x^2)/2-2x ?
The integral of (x^2)/2-2x is (x^3)/6-x^2+C