What is (\partial)/(\partial t)(cos(3t)) ?

The answer to (\partial)/(\partial t)(cos(3t)) is -sin(3t)*3

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(\partial)/(\partial t)(cos(3t))

\frac{\partial}{\partial t} (cos (3 t))

- sin (3 t) \cdot 3

Solution steps

\frac{\partial}{\partial t} (cos (3 t))

Apply the chain rule:

- sin (3 t) \frac{\partial}{\partial t} (3 t)

= - sin (3 t) \frac{\partial}{\partial t} (3 t)

\frac{\partial}{\partial t} (3 t) = 3

= - sin (3 t) \cdot 3

\frac{x ^{2}}{2 ( 1 - x )}

f (x) = lo g_{6} (2 x^{2} + 4), at x = 4

(- 1, - 5), (1, - 2)

e^{t} \cdot sin (2 t)

t \to 2 lim (sin (\frac{π}{4} t))

What is (\partial)/(\partial t)(cos(3t)) ?
The answer to (\partial)/(\partial t)(cos(3t)) is -sin(3t)*3