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Popular >

y^'=y(100-y)

Solution

y^{^{'}} = y (100 - y)

Solution

y = \frac{100}{- e ^{- 100 t - c_{1}} + 1}

Solution steps

y^{'} (t) = y (100 - y)

Solve Bernoulli ODE:

y = \frac{100}{- e ^{- 100 t - c_{1}} + 1}

y = \frac{100}{- e ^{- 100 t - c_{1}} + 1}

Popular Examples

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(dy)/(dx)-y/x =3xe^x,y(1)=3e-2

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\int (x)^{3} arccos (x) d x

Frequently Asked Questions (FAQ)

What is the solution for y^'=y(100-y) ?
The solution for y^'=y(100-y) is y=(100)/(-e^{-100t-c_{1)}+1}