What is (\partial)/(\partial x)(x^3-6x^2-34x+40) ?

The answer to (\partial)/(\partial x)(x^3-6x^2-34x+40) is 3x^2-12x-34

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(\partial)/(\partial x)(x^3-6x^2-34x+40)

\frac{\partial}{\partial x} (x^{3} - 6 x^{2} - 34 x + 40)

3 x^{2} - 12 x - 34

Solution steps

\frac{\partial}{\partial x} (x^{3} - 6 x^{2} - 34 x + 40)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (x^{3}) - \frac{\partial}{\partial x} (6 x^{2}) - \frac{\partial}{\partial x} (34 x) + \frac{\partial}{\partial x} (40)

\frac{\partial}{\partial x} (x^{3}) = 3 x^{2}

\frac{\partial}{\partial x} (6 x^{2}) = 12 x

\frac{\partial}{\partial x} (34 x) = 34

\frac{\partial}{\partial x} (40) = 0

= 3 x^{2} - 12 x - 34 + 0

Simplify

= 3 x^{2} - 12 x - 34

f (x) = x (x - 3)

\frac{d}{d x} ((3 x - 1)^{4} (- 2 x + 9)^{5})

\frac{d}{d p} (\frac{400}{p ^{2}})

\int (9 x^{2} - 6 x + 5) d x

f (x) = \frac{x}{x + \frac{c}{x}}

What is (\partial)/(\partial x)(x^3-6x^2-34x+40) ?
The answer to (\partial)/(\partial x)(x^3-6x^2-34x+40) is 3x^2-12x-34