What is the solution for y^'=(cos^2(x))(cos^2(2y)) ?

The solution for y^'=(cos^2(x))(cos^2(2y)) is y=(arctan(x+1/2 sin(2x)+c_{1}))/2+(pin)/2

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y^'=(cos^2(x))(cos^2(2y))

y^{^{'}} = (cos^{2} (x)) (cos^{2} (2 y))

y = \frac{arctan ( x + \frac{1}{2} sin ( 2 x ) + c _{1} )}{2} + \frac{πn}{2}

Solution steps

y^{'} (x) = (cos^{2} (x)) (cos^{2} (2 y))

Solve separable ODE:

y = \frac{arctan ( x + \frac{1}{2} sin ( 2 x ) + c _{1} )}{2} + \frac{πn}{2}

y = \frac{arctan ( x + \frac{1}{2} sin ( 2 x ) + c _{1} )}{2} + \frac{πn}{2}

\frac{d}{d x} (\frac{3 a x ^{2} + x}{2 x})

\int + e^{x} cos (x) d x

\int 15 sec^{5} (x) d x

\frac{d}{d x} (cos (x) (sin (x)))

What is the solution for y^'=(cos^2(x))(cos^2(2y)) ?
The solution for y^'=(cos^2(x))(cos^2(2y)) is y=(arctan(x+1/2 sin(2x)+c_{1}))/2+(pin)/2