What is the solution for y^{''}-7y+10y=0 ?

The solution for y^{''}-7y+10y=0 is y=c_{1}cos(sqrt(3)t)+c_{2}sin(sqrt(3)t)

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y^{''}-7y+10y=0

y^{^{''}} - 7 y + 10 y = 0

y = c_{1} cos (3 t) + c_{2} sin (3 t)

Solution steps

y^{''} (t) - 7 y + 10 y = 0

Solve linear ODE:

y = c_{1} cos (3 t) + c_{2} sin (3 t)

y = c_{1} cos (3 t) + c_{2} sin (3 t)

\int \frac{5}{1 + 5 x} d x

f (x) = x^{7} - \frac{1}{x ^{7}}

\frac{d}{d x} (\frac{3}{x} - 2)

\frac{d y}{d x} = e^{2 x}

\frac{x}{7 - 3 x}

What is the solution for y^{''}-7y+10y=0 ?
The solution for y^{''}-7y+10y=0 is y=c_{1}cos(sqrt(3)t)+c_{2}sin(sqrt(3)t)