What is the derivative of f(t)=(1+sqrt(t))(2t^2-7) ?

The derivative of f(t)=(1+sqrt(t))(2t^2-7) is (10t^2+8tsqrt(t)-7)/(2sqrt(t))

What is the first derivative of f(t)=(1+sqrt(t))(2t^2-7) ?

The first derivative of f(t)=(1+sqrt(t))(2t^2-7) is (10t^2+8tsqrt(t)-7)/(2sqrt(t))

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derivative of

f (t) = (1 + t) (2 t^{2} - 7)

\frac{10 t ^{2} + 8 t t - 7}{2 t}

Solution steps

\frac{d}{d t} ((1 + t) (2 t^{2} - 7))

Apply the Product Rule:

(f \cdot g)^{'} = f^{'} \cdot g + f \cdot g^{'}

f = 1 + t, g = 2 t^{2} - 7

= \frac{d}{d t} (1 + t) (2 t^{2} - 7) + \frac{d}{d t} (2 t^{2} - 7) (1 + t)

\frac{d}{d t} (1 + t) = \frac{1}{2 t}

\frac{d}{d t} (2 t^{2} - 7) = 4 t

= \frac{1}{2 t} (2 t^{2} - 7) + 4 t (1 + t)

Simplify

\frac{1}{2 t} (2 t^{2} - 7) + 4 t (1 + t) : \frac{10 t ^{2} + 8 t t - 7}{2 t}

= \frac{10 t ^{2} + 8 t t - 7}{2 t}

\int x^{1} \frac{( 5 x ^{2} + \frac{2}{3} ) ^{4}}{1} d x

\frac{d}{d t} ((\frac{d}{d t} (e^{t} cos (t)))^{2})

f (x) = \frac{e ^{x^{2}}}{x ^{3}}

x \to - 3 lim (2 x^{2} - 3 x + 4)

\frac{d}{d x} (x^{3} - 9 x^{2} + 24 x - 15)

What is the derivative of f(t)=(1+sqrt(t))(2t^2-7) ?
The derivative of f(t)=(1+sqrt(t))(2t^2-7) is (10t^2+8tsqrt(t)-7)/(2sqrt(t))
What is the first derivative of f(t)=(1+sqrt(t))(2t^2-7) ?
The first derivative of f(t)=(1+sqrt(t))(2t^2-7) is (10t^2+8tsqrt(t)-7)/(2sqrt(t))