What is (\partial)/(\partial x)(1+xln(xy-7)) ?

The answer to (\partial)/(\partial x)(1+xln(xy-7)) is (xy)/(xy-7)+ln(xy-7)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(\partial)/(\partial x)(1+xln(xy-7))

\frac{\partial}{\partial x} (1 + x ln (x y - 7))

\frac{x y}{x y - 7} + ln (x y - 7)

Solution steps

\frac{\partial}{\partial x} (1 + x ln (x y - 7))

Treat

y

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (1) + \frac{\partial}{\partial x} (x ln (x y - 7))

\frac{\partial}{\partial x} (1) = 0

\frac{\partial}{\partial x} (x ln (x y - 7)) = ln (y x - 7) + \frac{y x}{y x - 7}

= 0 + ln (y x - 7) + \frac{y x}{y x - 7}

Simplify

= \frac{x y}{x y - 7} + ln (x y - 7)

\frac{d x}{d t} = 30 - \frac{3 x}{100}

x \to 2 lim (3 \cdot 6 + 6.6)

f (x) = 168 (2 x + 5)^{5}

3 y^{^{''}} + y^{^{'}} = 0

What is (\partial)/(\partial x)(1+xln(xy-7)) ?
The answer to (\partial)/(\partial x)(1+xln(xy-7)) is (xy)/(xy-7)+ln(xy-7)