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Popular >

y^'cot(x)+y=2

Solution

y^{^{'}} cot (x) + y = 2

Solution

y = - c_{1} cos (x) + 2

Solution steps

y^{'} (x) cot (x) + y = 2

Solve separable ODE:

y = - c_{1} cos (x) + 2

y = - c_{1} cos (x) + 2

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Frequently Asked Questions (FAQ)

What is the solution for y^'cot(x)+y=2 ?
The solution for y^'cot(x)+y=2 is y=-c_{1}cos(x)+2