What is the derivative of A(2xe^x+e^xx^2) ?

The derivative of A(2xe^x+e^xx^2) is A(e^xx^2+4e^xx+2e^x)

What is the first derivative of A(2xe^x+e^xx^2) ?

The first derivative of A(2xe^x+e^xx^2) is A(e^xx^2+4e^xx+2e^x)

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\frac{d}{d x} (A (2 x e^{x} + e^{x} x^{2}))

A (e^{x} x^{2} + 4 e^{x} x + 2 e^{x})

Solution steps

\frac{d}{d x} (A (2 x e^{x} + e^{x} x^{2}))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= A \frac{d}{d x} (2 x e^{x} + e^{x} x^{2})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= A (\frac{d}{d x} (2 x e^{x}) + \frac{d}{d x} (e^{x} x^{2}))

\frac{d}{d x} (2 x e^{x}) = 2 (e^{x} + e^{x} x)

\frac{d}{d x} (e^{x} x^{2}) = e^{x} x^{2} + 2 x e^{x}

= A (2 (e^{x} + e^{x} x) + e^{x} x^{2} + 2 x e^{x})

Expand

2 (e^{x} + e^{x} x) + e^{x} x^{2} + 2 x e^{x} : e^{x} x^{2} + 4 e^{x} x + 2 e^{x}

= A (e^{x} x^{2} + 4 e^{x} x + 2 e^{x})

x \to 2 lim (\frac{1}{2})

\frac{d}{d x} (- x^{\frac{2}{3}} (x - 4))

\int \frac{3}{2} x d x

\int (2 x - x^{2})^{2} d x

\frac{d}{d x} (2 a x - x^{2})

What is the derivative of A(2xe^x+e^xx^2) ?
The derivative of A(2xe^x+e^xx^2) is A(e^xx^2+4e^xx+2e^x)
What is the first derivative of A(2xe^x+e^xx^2) ?
The first derivative of A(2xe^x+e^xx^2) is A(e^xx^2+4e^xx+2e^x)