What is (\partial)/(\partial y)(2xsin(y)) ?

The answer to (\partial)/(\partial y)(2xsin(y)) is 2xcos(y)

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(\partial)/(\partial y)(2xsin(y))

\frac{\partial}{\partial y} (2 x sin (y))

2 x cos (y)

Solution steps

\frac{\partial}{\partial y} (2 x sin (y))

Treat

x

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 2 x \frac{\partial}{\partial y} (sin (y))

Apply the common derivative:

\frac{\partial}{\partial y} (sin (y)) = cos (y)

= 2 x cos (y)

v \to 4 + lim (\frac{4 - v}{∣ 4 - v ∣})

\frac{\partial}{\partial x} (x^{2} + 5)

cos^{2} (8 t)

\int_{- 1}^{1} (x^{2}) d x

\frac{d}{d x} (\frac{e ^{3 x}}{x ^{12}})

What is (\partial)/(\partial y)(2xsin(y)) ?
The answer to (\partial)/(\partial y)(2xsin(y)) is 2xcos(y)