What is the solution for y^{''}+11y^'-28y=0 ?

The solution for y^{''}+11y^'-28y=0 is y=c_{1}e^{((-11+sqrt(233))t)/2}+c_{2}e^{((-11-sqrt(233))t)/2}

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y^{''}+11y^'-28y=0

y^{^{''}} + 11 y^{^{'}} - 28 y = 0

y = c_{1} e^{\frac{( - 11 + 233 ) t}{2}} + c_{2} e^{\frac{( - 11 - 233 ) t}{2}}

Solution steps

y^{''} (t) + 11 y^{'} (t) - 28 y = 0

Solve linear ODE:

y = c_{1} e^{\frac{( - 11 + 233 ) t}{2}} + c_{2} e^{\frac{( - 11 - 233 ) t}{2}}

y = c_{1} e^{\frac{( - 11 + 233 ) t}{2}} + c_{2} e^{\frac{( - 11 - 233 ) t}{2}}

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What is the solution for y^{''}+11y^'-28y=0 ?
The solution for y^{''}+11y^'-28y=0 is y=c_{1}e^{((-11+sqrt(233))t)/2}+c_{2}e^{((-11-sqrt(233))t)/2}