What is (\partial)/(\partial x)(3x^4-65x^3) ?

The answer to (\partial)/(\partial x)(3x^4-65x^3) is 12x^3-195x^2

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(\partial)/(\partial x)(3x^4-65x^3)

\frac{\partial}{\partial x} (3 x^{4} - 65 x^{3})

12 x^{3} - 195 x^{2}

Solution steps

\frac{\partial}{\partial x} (3 x^{4} - 65 x^{3})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (3 x^{4}) - \frac{\partial}{\partial x} (65 x^{3})

\frac{\partial}{\partial x} (3 x^{4}) = 12 x^{3}

\frac{\partial}{\partial x} (65 x^{3}) = 195 x^{2}

= 12 x^{3} - 195 x^{2}

\int_{0}^{\frac{π}{6}} cos (3 x) d x

y^{^{''}} + y = cos (t), y (0) = 0, y^{^{'}} (0) = 0

x \to - 3 + lim (ln (x + 3))

(4 x^{2} - y^{2}) d x - x y d y = 0

y^{^{'}} = 2 (2 x + y)^{2}

What is (\partial)/(\partial x)(3x^4-65x^3) ?
The answer to (\partial)/(\partial x)(3x^4-65x^3) is 12x^3-195x^2