What is the integral of sqrt((2+x)/(2-x)) ?

The integral of sqrt((2+x)/(2-x)) is -sqrt(x+2)sqrt(2-x)+4arctan(sqrt((x+2)/(2-x)))+C

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integral of sqrt((2+x)/(2-x))

\int \frac{2 + x}{2 - x} d x

- x + 2 2 - x + 4 arctan (\frac{x + 2}{2 - x}) + C

Solution steps

\int \frac{2 + x}{2 - x} d x

Apply u-substitution

: \int - \frac{- u + 4}{u} d u

= \int - \frac{- u + 4}{u} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= - \int \frac{- u + 4}{u} d u

Expand

\frac{- u + 4}{u} : - 1 + \frac{4}{u}

= - \int - 1 + \frac{4}{u} d u

Apply u-substitution

: \int - \frac{4 v - 1}{v ^{2}} d v

= - \int - \frac{4 v - 1}{v ^{2}} d v

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= - (- 4 \cdot \int \frac{v - 1}{v ^{2}} d v)

Apply Integration By Parts

: - \frac{v - 1}{v} - \int - \frac{1}{2 v v - 1} d v

= - (- 4 (- \frac{v - 1}{v} - \int - \frac{1}{2 v v - 1} d v))

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= - (- 4 (- \frac{v - 1}{v} - (- \frac{1}{2} \cdot \int \frac{1}{v v - 1} d v)))

Apply u-substitution

: \int \frac{2}{w ^{2} + 1} d w

= - (- 4 (- \frac{v - 1}{v} - (- \frac{1}{2} \cdot \int \frac{2}{w ^{2} + 1} d w)))

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= - (- 4 (- \frac{v - 1}{v} - (- \frac{1}{2} \cdot 2 \cdot \int \frac{1}{w ^{2} + 1} d w)))

Use the common integral:

\int \frac{1}{w ^{2} + 1} d w = arctan (w)

= - (- 4 (- \frac{v - 1}{v} - (- \frac{1}{2} \cdot 2 arctan (w))))

Substitute back

= - - 4 - \frac{\frac{4}{2 - x} - 1}{\frac{4}{2 - x}} - (- \frac{1}{2} \cdot 2 arctan (\frac{4}{2 - x} - 1))

Simplify

- - 4 - \frac{\frac{4}{2 - x} - 1}{\frac{4}{2 - x}} - (- \frac{1}{2} \cdot 2 arctan (\frac{4}{2 - x} - 1)) : - x + 2 2 - x + 4 arctan (\frac{x + 2}{2 - x})

= - x + 2 2 - x + 4 arctan (\frac{x + 2}{2 - x})

Add a constant to the solution

= - x + 2 2 - x + 4 arctan (\frac{x + 2}{2 - x}) + C

\frac{\partial}{\partial x} (\frac{1}{2 x ^{\frac{1}{2}}})

y = 20 x

y^{^{'''}} - 2 y^{^{''}} - y + 2 y = 0

x \to 0 lim (\frac{3 x ^{2} - 8 x}{x})

f (x) = \frac{7 + 2 ln ( x )}{x}

What is the integral of sqrt((2+x)/(2-x)) ?
The integral of sqrt((2+x)/(2-x)) is -sqrt(x+2)sqrt(2-x)+4arctan(sqrt((x+2)/(2-x)))+C