What is the tangent of f(x)=x^2-6,(-2,-2) ?

The tangent of f(x)=x^2-6,(-2,-2) is y=-4x-10

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

tangent of f(x)=x^2-6,(-2,-2)

tangent of

f (x) = x^{2} - 6, (- 2, - 2)

y = - 4 x - 10

Solution steps

Find the slope of

f (x) = x^{2} - 6 : \frac{df ( x )}{d x} = 2 x

Compute the slope of

f (x) = x^{2} - 6

(- 2, - 2) : m = - 4

Find the line with slope m=

- 4

and passing through

(- 2, - 2) : y = - 4 x - 10

y = - 4 x - 10

\frac{d}{d x} (a \cdot sin (x) + b \cdot cos (x))

x \to 9 lim (5 + x^{2})

\int_{0}^{8} \frac{1}{64 - x ^{2}} d x

\frac{d}{d x} (e^{3 x} sin (3 x))

x \to \infty lim (x^{2} - 2)

What is the tangent of f(x)=x^2-6,(-2,-2) ?
The tangent of f(x)=x^2-6,(-2,-2) is y=-4x-10