What is the integral of 1/(sqrt(529+x^2)) ?

The integral of 1/(sqrt(529+x^2)) is ln(1/23 |x+sqrt(529+x^2)|)+C

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integral of 1/(sqrt(529+x^2))

\int \frac{1}{529 + x ^{2}} d x

ln (\frac{1}{23} x + 529 + x^{2}) + C

Solution steps

\int \frac{1}{529 + x ^{2}} d x

Apply Trigonometric Substitution

: \int sec (u) d u

= \int sec (u) d u

Use the common integral:

\int sec (u) d u = ln ∣ tan (u) + sec (u) ∣

= ln ∣ tan (u) + sec (u) ∣

Substitute back

u = arctan (\frac{1}{23} x)

= ln tan (arctan (\frac{1}{23} x)) + sec (arctan (\frac{1}{23} x))

Simplify

ln tan (arctan (\frac{1}{23} x)) + sec (arctan (\frac{1}{23} x)) : ln (\frac{1}{23} x + 529 + x^{2})

= ln (\frac{1}{23} x + 529 + x^{2})

Add a constant to the solution

= ln (\frac{1}{23} x + 529 + x^{2}) + C

\frac{d}{d x} (9 ln (x))

11 e^{x}

\int \frac{1}{2} x^{\frac{1}{2}} d x

x \to 4 lim (x^{2} - 3 x + 7)

x \to 3 lim (0)

What is the integral of 1/(sqrt(529+x^2)) ?
The integral of 1/(sqrt(529+x^2)) is ln(1/23 |x+sqrt(529+x^2)|)+C