What is the derivative of-t^2+2t+4 ?

The derivative of-t^2+2t+4 is -2t+2

What is the first derivative of-t^2+2t+4 ?

The first derivative of-t^2+2t+4 is -2t+2

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derivative of

- t^{2} + 2 t + 4

- 2 t + 2

Solution steps

\frac{d}{d t} (- t^{2} + 2 t + 4)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= - \frac{d}{d t} (t^{2}) + \frac{d}{d t} (2 t) + \frac{d}{d t} (4)

\frac{d}{d t} (t^{2}) = 2 t

\frac{d}{d t} (2 t) = 2

\frac{d}{d t} (4) = 0

= - 2 t + 2 + 0

Simplify

= - 2 t + 2

\frac{d y}{d x} = \frac{1}{1 + x ^{2}}

\frac{5 s}{s ^{2} + 4 s + 5}

(2 y + 2 t - 9) d t + (4 y + 2 t - 1) d y = 0

\int (3 - x)^{2} d x

f^{'} (x) = f (x) (1 - f (x))

What is the derivative of-t^2+2t+4 ?
The derivative of-t^2+2t+4 is -2t+2
What is the first derivative of-t^2+2t+4 ?
The first derivative of-t^2+2t+4 is -2t+2