What is the solution for (6-10y+e^{-5x})dx-2dy=0 ?

The solution for (6-10y+e^{-5x})dx-2dy=0 is y= x/(2e^{5x)}+3/5+(c_{1})/(e^{5x)}

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(6-10y+e^{-5x})dx-2dy=0

(6 - 10 y + e^{- 5 x}) d x - 2 d y = 0

y = \frac{x}{2 e ^{5 x}} + \frac{3}{5} + \frac{c _{1}}{e ^{5 x}}

Solution steps

(6 - 10 y + e^{- 5 x}) d x - 2 d y = 0

Solve linear ODE:

y = \frac{x}{2 e ^{5 x}} + \frac{3}{5} + \frac{c _{1}}{e ^{5 x}}

y = \frac{x}{2 e ^{5 x}} + \frac{3}{5} + \frac{c _{1}}{e ^{5 x}}

\frac{2 - s}{s ^{2} + 6 s + 34}

\frac{1 - x}{1 + x}

\frac{d}{d x} ((cos^{2} (x)) x)

\frac{\partial}{\partial x} (x y)

\frac{10}{( x ^{2} - 7 ) ^{4}}

What is the solution for (6-10y+e^{-5x})dx-2dy=0 ?
The solution for (6-10y+e^{-5x})dx-2dy=0 is y= x/(2e^{5x)}+3/5+(c_{1})/(e^{5x)}