What is the derivative of f(x)=arccos(x) ?

The derivative of f(x)=arccos(x) is -1/(sqrt(1-x^2))

What is the first derivative of f(x)=arccos(x) ?

The first derivative of f(x)=arccos(x) is -1/(sqrt(1-x^2))

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

derivative of

f (x) = arccos (x)

- \frac{1}{1 - x ^{2}}

Solution steps

\frac{d}{d x} (arccos (x))

Apply the common derivative:

\frac{d}{d x} (arccos (x)) = - \frac{1}{1 - x ^{2}}

= - \frac{1}{1 - x ^{2}}

\frac{d}{d x} (3 sin (x) + 2 cos (x))

\int 6 x^{6} d x

\frac{d}{d x} (\frac{e ^{x}}{4 - x})

y^{^{''}} - 2 y^{^{'}} + y = t e^{t}

\int p (p + 5)^{5} d p

What is the derivative of f(x)=arccos(x) ?
The derivative of f(x)=arccos(x) is -1/(sqrt(1-x^2))
What is the first derivative of f(x)=arccos(x) ?
The first derivative of f(x)=arccos(x) is -1/(sqrt(1-x^2))