What is the derivative of g(x)=sqrt(6-7x) ?

The derivative of g(x)=sqrt(6-7x) is -7/(2sqrt(6-7x))

What is the first derivative of g(x)=sqrt(6-7x) ?

The first derivative of g(x)=sqrt(6-7x) is -7/(2sqrt(6-7x))

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derivative of

g (x) = 6 - 7 x

- \frac{7}{2 6 - 7 x}

Solution steps

\frac{d}{d x} (6 - 7 x)

Apply the chain rule:

\frac{1}{2 6 - 7 x} \frac{d}{d x} (6 - 7 x)

= \frac{1}{2 6 - 7 x} \frac{d}{d x} (6 - 7 x)

\frac{d}{d x} (6 - 7 x) = - 7

= \frac{1}{2 6 - 7 x} (- 7)

Simplify

\frac{1}{2 6 - 7 x} (- 7) : - \frac{7}{2 6 - 7 x}

= - \frac{7}{2 6 - 7 x}

f (x) = x - 2 x^{2}, at x = 1

\int \frac{1}{x ^{2} + 6 x + 10} d x

\int 33 sec^{4} (x) d x

y^{^{'}} = t^{2} y

y^{^{'}} = y + 2

What is the derivative of g(x)=sqrt(6-7x) ?
The derivative of g(x)=sqrt(6-7x) is -7/(2sqrt(6-7x))
What is the first derivative of g(x)=sqrt(6-7x) ?
The first derivative of g(x)=sqrt(6-7x) is -7/(2sqrt(6-7x))