What is the integral of-x^2(sqrt(3))/3 ?

The integral of-x^2(sqrt(3))/3 is -(x^3)/(3sqrt(3))+C

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integral of-x^2(sqrt(3))/3

\int - x^{2} \frac{3}{3} d x

- \frac{x ^{3}}{3 3} + C

Solution steps

\int - x^{2} \frac{3}{3} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= - \frac{3}{3} \cdot \int x^{2} d x

- \frac{3}{3} = - \frac{1}{3}

= - \frac{1}{3} \cdot \int x^{2} d x

Apply the Power Rule

: \frac{x ^{3}}{3}

= - \frac{1}{3} \cdot \frac{x ^{3}}{3}

Simplify

- \frac{1}{3} \cdot \frac{x ^{3}}{3} : - \frac{x ^{3}}{3 3}

= - \frac{x ^{3}}{3 3}

Add a constant to the solution

= - \frac{x ^{3}}{3 3} + C

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\int_{0}^{2} \frac{1}{x ^{2} + 4} d x

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\int \frac{1}{s + 1} d s

What is the integral of-x^2(sqrt(3))/3 ?
The integral of-x^2(sqrt(3))/3 is -(x^3)/(3sqrt(3))+C