What is the integral of 10sec^2(x) ?

The integral of 10sec^2(x) is 10tan(x)+C

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integral of 10sec^2(x)

\int 10 sec^{2} (x) d x

10 tan (x) + C

Solution steps

\int 10 sec^{2} (x) d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 10 \cdot \int sec^{2} (x) d x

Use the common integral:

\int sec^{2} (x) d x = tan (x)

= 10 tan (x)

Add a constant to the solution

= 10 tan (x) + C

\frac{d}{d x} ((- 9 x^{2} + 4)^{2})

y = 2 x - x^{2}, y = 0

\frac{d}{d x} (y + x)

cos (π x) (π)

\frac{d}{d x} ((x^{2} - 1) (x - 1))