What is the derivative of (8x)^{6x} ?

The derivative of (8x)^{6x} is 9ln(2)*2^{18x+1}x^{6x}+3*2^{1+18x}x^{6x}(ln(x)+1)

What is the first derivative of (8x)^{6x} ?

The first derivative of (8x)^{6x} is 9ln(2)*2^{18x+1}x^{6x}+3*2^{1+18x}x^{6x}(ln(x)+1)

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derivative of

(8 x)^{6 x}

9 ln (2) \cdot 2^{18 x + 1} x^{6 x} + 3 \cdot 2^{1 + 18 x} x^{6 x} (ln (x) + 1)

Solution steps

\frac{d}{d x} ((8 x)^{6 x})

Simplify

(8 x)^{6 x} : 26214 4^{x} x^{6 x}

= \frac{d}{d x} (26214 4^{x} x^{6 x})

Apply the Product Rule:

(f \cdot g)^{'} = f^{'} \cdot g + f \cdot g^{'}

f = 26214 4^{x}, g = x^{6 x}

= \frac{d}{d x} (26214 4^{x}) x^{6 x} + \frac{d}{d x} (x^{6 x}) 26214 4^{x}

\frac{d}{d x} (26214 4^{x}) = 9 ln (2) \cdot 2^{18 x + 1}

\frac{d}{d x} (x^{6 x}) = 6 x^{6 x} (ln (x) + 1)

= 9 ln (2) \cdot 2^{18 x + 1} x^{6 x} + 6 x^{6 x} (ln (x) + 1) \cdot 26214 4^{x}

6 x^{6 x} (ln (x) + 1) \cdot 26214 4^{x} = 3 \cdot 2^{1 + 18 x} x^{6 x} (ln (x) + 1)

= 9 ln (2) \cdot 2^{18 x + 1} x^{6 x} + 3 \cdot 2^{1 + 18 x} x^{6 x} (ln (x) + 1)

6 x e^{- x^{2}}

x \to \infty lim (- e^{2 x})

y^{^{'}} = x + y, y (0) = 3

\frac{d y}{d x} + 5 y = 70

\int (1 + tan (x)) d x

What is the derivative of (8x)^{6x} ?
The derivative of (8x)^{6x} is 9ln(2)*2^{18x+1}x^{6x}+3*2^{1+18x}x^{6x}(ln(x)+1)
What is the first derivative of (8x)^{6x} ?
The first derivative of (8x)^{6x} is 9ln(2)*2^{18x+1}x^{6x}+3*2^{1+18x}x^{6x}(ln(x)+1)