What is the derivative of 6xe^{-x^2} ?

The derivative of 6xe^{-x^2} is 6(e^{-x^2}-2e^{-x^2}x^2)

What is the first derivative of 6xe^{-x^2} ?

The first derivative of 6xe^{-x^2} is 6(e^{-x^2}-2e^{-x^2}x^2)

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derivative of

6 x e^{- x^{2}}

6 (e^{- x^{2}} - 2 e^{- x^{2}} x^{2})

Solution steps

\frac{d}{d x} (6 x e^{- x^{2}})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 6 \frac{d}{d x} (x e^{- x^{2}})

Apply the Product Rule:

(f \cdot g)^{'} = f^{'} \cdot g + f \cdot g^{'}

f = x, g = e^{- x^{2}}

= 6 (\frac{d x}{d x} e^{- x^{2}} + \frac{d}{d x} (e^{- x^{2}}) x)

\frac{d x}{d x} = 1

\frac{d}{d x} (e^{- x^{2}}) = - 2 e^{- x^{2}} x

= 6 (1 \cdot e^{- x^{2}} + (- 2 e^{- x^{2}} x) x)

Simplify

6 (1 \cdot e^{- x^{2}} + (- 2 e^{- x^{2}} x) x) : 6 (e^{- x^{2}} - 2 e^{- x^{2}} x^{2})

= 6 (e^{- x^{2}} - 2 e^{- x^{2}} x^{2})

x \to \infty lim (- e^{2 x})

y^{^{'}} = x + y, y (0) = 3

\frac{d y}{d x} + 5 y = 70

\int (1 + tan (x)) d x

\int x tan^{4} (x^{2}) d x

What is the derivative of 6xe^{-x^2} ?
The derivative of 6xe^{-x^2} is 6(e^{-x^2}-2e^{-x^2}x^2)
What is the first derivative of 6xe^{-x^2} ?
The first derivative of 6xe^{-x^2} is 6(e^{-x^2}-2e^{-x^2}x^2)