What is the solution for y^{''}-3y^'+2y=e^x+2e^{3x} ?

The solution for y^{''}-3y^'+2y=e^x+2e^{3x} is y=c_{1}e^{2x}+c_{2}e^x-e^xx+e^{3x}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

y^{''}-3y^'+2y=e^x+2e^{3x}

y^{^{''}} - 3 y^{^{'}} + 2 y = e^{x} + 2 e^{3 x}

y = c_{1} e^{2 x} + c_{2} e^{x} - e^{x} x + e^{3 x}

Solution steps

y^{''} (x) - 3 y^{'} (x) + 2 y = e^{x} + 2 e^{3 x}

Solve linear ODE:

y = c_{1} e^{2 x} + c_{2} e^{x} - e^{x} x + e^{3 x}

y = c_{1} e^{2 x} + c_{2} e^{x} - e^{x} x + e^{3 x}

\frac{d}{d z} (y z)

\frac{\partial}{\partial x} (2 x y - x^{2} + y)

\int_{0}^{1} π (4 - \frac{3}{2} x)^{2} d x

x \to \infty lim (\frac{10 x + 100}{x ^{2} - 30})

y (t + 2) y^{^{'}} + 1 = - t

What is the solution for y^{''}-3y^'+2y=e^x+2e^{3x} ?
The solution for y^{''}-3y^'+2y=e^x+2e^{3x} is y=c_{1}e^{2x}+c_{2}e^x-e^xx+e^{3x}