What is laplacetransform 2sin(3t)cos(3t) ?

The answer to laplacetransform 2sin(3t)cos(3t) is 6/(s^2+36)

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laplacetransform 2sin(3t)cos(3t)

laplace transform

2 sin (3 t) cos (3 t)

\frac{6}{s ^{2} + 36}

Solution steps

L {2 sin (3 t) cos (3 t)}

Rewrite using trig identities

L {sin (6 t)}

Use Laplace Transform table:

L {sin (a t)} = \frac{a}{s ^{2} + a ^{2}}

L {sin (6 t)} = \frac{6}{s ^{2} + 6 ^{2}}

= \frac{6}{s ^{2} + 6 ^{2}}

= \frac{6}{s ^{2} + 36}

\int (z + 3)^{4} d z

(3 x - 2)^{3} (8 x^{2} + 7)^{3}

- \frac{1}{2} x^{3} + 2 x^{2} + \frac{15}{2} x - 9, [1, 6]

\int_{- 1}^{1} 4 - 4 x^{2} d x

\frac{d}{d x} (\frac{4 - 2 x - x ^{2}}{x ^{2} - 6})

What is laplacetransform 2sin(3t)cos(3t) ?
The answer to laplacetransform 2sin(3t)cos(3t) is 6/(s^2+36)