What is the derivative of sinh^2(x/(1+x)) ?

The derivative of sinh^2(x/(1+x)) is (2cosh(x/(1+x))sinh(x/(1+x)))/((1+x)^2)

What is the first derivative of sinh^2(x/(1+x)) ?

The first derivative of sinh^2(x/(1+x)) is (2cosh(x/(1+x))sinh(x/(1+x)))/((1+x)^2)

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Popular >

\frac{d}{d x} (sinh^{2} (\frac{x}{1 + x}))

\frac{2 cosh ( \frac{x}{1 + x} ) sinh ( \frac{x}{1 + x} )}{( 1 + x ) ^{2}}

Solution steps

\frac{d}{d x} (sinh^{2} (\frac{x}{1 + x}))

Apply the chain rule:

2 sinh (\frac{x}{1 + x}) \frac{d}{d x} (sinh (\frac{x}{1 + x}))

= 2 sinh (\frac{x}{1 + x}) \frac{d}{d x} (sinh (\frac{x}{1 + x}))

\frac{d}{d x} (sinh (\frac{x}{1 + x})) = \frac{cosh ( \frac{x}{1 + x} )}{( 1 + x ) ^{2}}

= 2 sinh (\frac{x}{1 + x}) \frac{cosh ( \frac{x}{1 + x} )}{( 1 + x ) ^{2}}

Multiply fractions:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{2 cosh ( \frac{x}{1 + x} ) sinh ( \frac{x}{1 + x} )}{( 1 + x ) ^{2}}

\int \frac{50 x + 6}{( 7 x + 1 ) ( x - 1 )} d x

\int e^{4 x + 6} d x

y^{^{'}} = \frac{2 y}{x} - x y^{2}

6 sin (θ), 6 cos (θ)

\int \frac{ln ( 4 x )}{x} d x

What is the derivative of sinh^2(x/(1+x)) ?
The derivative of sinh^2(x/(1+x)) is (2cosh(x/(1+x))sinh(x/(1+x)))/((1+x)^2)
What is the first derivative of sinh^2(x/(1+x)) ?
The first derivative of sinh^2(x/(1+x)) is (2cosh(x/(1+x))sinh(x/(1+x)))/((1+x)^2)