What is (\partial)/(\partial x)(x^2-4xy) ?

The answer to (\partial)/(\partial x)(x^2-4xy) is 2x-4y

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(\partial)/(\partial x)(x^2-4xy)

\frac{\partial}{\partial x} (x^{2} - 4 x y)

2 x - 4 y

Solution steps

\frac{\partial}{\partial x} (x^{2} - 4 x y)

Treat

y

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (x^{2}) - \frac{\partial}{\partial x} (4 x y)

\frac{\partial}{\partial x} (x^{2}) = 2 x

\frac{\partial}{\partial x} (4 x y) = 4 y

= 2 x - 4 y

\int e^{7 x} sin (8 x) d x

y^{^{'}} = x \cdot y

\frac{\partial}{\partial x} (x^{7} + 4^{y} + x^{y})

(e^{2 x}), - 2

\frac{d}{d x} (\frac{e ^{- x}}{x + 1})

What is (\partial)/(\partial x)(x^2-4xy) ?
The answer to (\partial)/(\partial x)(x^2-4xy) is 2x-4y